Solución al ejercicio 7610

a) \bf N = N_0\cdot e^{-\lambda \cdot t}
b) Si t < t_{1/2}(A)\ \to\ \bf A_A < A_B
Si t = t_{1/2}(A)\ \to\ \bf A_A = A_B
Si t > t_{1/2}(A)\ \to\ \bf A_A > A_B